-5<_(less than or equal too)-3x+1<10?

Answer 1

-5<_-3x+1<10
Divide into two equations:
-5<_-3x+1 and -3x+1<10
Solve both equations
(1) -5<_-3x+1(add 1 to both sides)
-4<_-3x (Divide both sides by -3, flip sign because dividing by a negative)
4/3>_x
(2) -3x+1<10 (Subtract 1 to both sides)
-3x<9 (Divide both sides by -3 and flip the sign because you are diving by a negative)
x>-3

-3

Answer 2

-5<_-3x+1<10
subtract the one from (-3x+1)..from all three areas.
-5-1=-6<_-3x<10-1= -6<_-3<9.
Now you divide the three away from x. Divide three from all three.
-6/3=-2<_x<9/3
-2<_x<3

Answer 3

-5 <= -3x+1 < 10
Subtract 1 from each term getting:
-6 <= -3x <9
Divide each term by 3getting:
-2 <= -x < 3
Multiply each term by -1 and reverse signs getting:
2 >= x > -3

Answer 4

Divide into two equations:
-5<_3x+1:
-6<_3x
3x>_-6
thus, x>_-2

or
3x+1<1
3x<0
x<0

Thus, x<0,x>_-2