and also
2x^2y - 6xy^2 + 12xy / 2xy
2007-10-08 09:47:35 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
-15xy - 10x / 5x = -3y - 2
2x^2y - 6xy^2 + 12xy / 2xy =
(2x^2y) / 2xy - 6xy^2 / (2xy) + 12xy / (2xy) =
x - 3y + 6
2007-10-08 09:56:09 · answer #1 · answered by Will 4 · 0⤊ 0⤋
I can't tell if you mean -15xy - (10x / 5x) or (-15xy - 10x) / 5x. Assuming it's the later, think of this as (-15xy - 10x) * (1 / 5x)
Then you can use the distributive rule, dividing each of the numerator terms by 5 and by x to get -3y - 2.
2007-10-08 09:52:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Question 1
(- 5x) (3y + 2) / (5x)
(-1) (3y + 2)
- (3y + 2)
Question 2
(2xy) (x - 3y + 6) / (2xy)
x - 3y + 6
2007-10-08 10:56:55 · answer #3 · answered by Como 7 · 1⤊ 0⤋
1. -3y - 2
2. [(2x^2y)/2xy] - 18xy + 6
2007-10-08 10:00:55 · answer #4 · answered by James M 2 · 0⤊ 0⤋
-5y-2
and
x-3y+6
2007-10-08 09:52:06 · answer #5 · answered by Anonymous · 0⤊ 1⤋
factor out and cance !
2007-10-08 09:56:19 · answer #6 · answered by rocha_diego@sbcglobal.net 2 · 0⤊ 0⤋
Please clarify...
is it
(-15xy - 10x)/5x
or
-15xy - (10x/5x)
also the second one
2007-10-08 09:56:37 · answer #7 · answered by Richard B 3 · 0⤊ 0⤋