PLEASE HELP ME PHYSICS short question about Work and Kinetic Energy!!!?

Question

A 4.0 kg block is pushed 4.2 m up a rough 37° inclined plane by a horizontal force of 75 N. If the initial speed of the block is 2.2 m/s up the plane and a constant kinetic friction force of 25 N opposes the motion, ­calculate the following.

a) the initial kinetic energy of the block
=....J
(b) the work done by the 75 N force
=....J
(c) the work done by the friction force
=....J
(d) the work done by gravity
=....J
(e) the work done by the normal force
= 0 J
(f) the final kinetic energy of the block
=....J

Answer 1

Initial
.5*4*2.2^2
=9.68 J

b) Work is F*d
75*4.2
=315 J

c) Friction
25*4.2
-105

d) Gravity
m*g*h
h=4.2*sin(37)
-99.1

e) the normal force work is zero.

f) 9.68+315-105-99.1
KE=120.6 J



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