Factorising Question, (please answer)?

Question

How did this happen?
x^3-2x^2-3x
=x(x^2-2x-3)
=(x-3) (x+1) <---

How did it become =(x-3) (x+1)?
Please explain easily, because this equation is very annoying, especially when I dont understand how the answer happened...

oops, sorry I left out the x by mistake:

x(x-3) (x+1)

Answer 1

Which idiot told you the answer?

Answer: x(x-3)(x+1)
___________________________

x^3 - 2x^2 - 3x

Factor out x.

x(x^2 - 2x - 3)

Try to factor x^2 - 2x - 3

Which numbers add to -2 and multiply to -3?

Only -3 and 1

x(x-3)(x+1)

Answer 2

x ³ - 2 x ² - 3 x
x (x ² - 2 x - 3)
have now to factorise x ² - 2 x - 3:-
factors for x² are x and x
(x ------) (x-------)
now require factors for 3:-
these are 3 and 1
(x----3) (x----1)
Now allocate signs to obtain - 3 and - 2x:-
(x - 3) (x + 1)
Answer is ( x ) (x - 3) (x + 1)

Answer 3

factor out and and then you factor the inside and set the x on the outside to x=0 and then you are just left with x-3 and x+1

Answer 4

when you FOIL, you look for (x + _)(x + _) such that added together they'll equal B, or the coefficient of x, which is -2, and the also need to be multiplied to equal C, the constant, which is -3, the only two number that do this are -3, and 1
which is now why its (x + -3)(x + 1) or (x - 3)(x + 1)

Answer 5

You dropped the x outside the parentheses
x(x-3)(x+1). You don't have an equation. The x outside the parentheses should still be there.