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for some reason i have gone brain dead at the moment and forgot completely on how to do this.. im looking at like its easy but... its one of those days

2007-10-08 06:49:19 · 10 answers · asked by Nick 4 in Science & Mathematics Mathematics

10 answers

x^2-2x-15=0

(x-5)(x+3)=0
x=5 x= -3

2007-10-08 06:51:56 · answer #1 · answered by mrr86 5 · 1 0

Okay so you are given x^2 - 2x = 15

Subtract 15 from both sides and you have

x^2 - 2x - 15 = 0

So now factor.

x is multiplied by x to get x^2. So far, you have

(x )(x )

Now you need to ask how you get -2 using a negative number and a positive number that also multiply to get 15.

You can get -2 by doing -5 + 3. -5 * 3 gives you 15 as well.

So you have

(x - 5)(x+3)=0

The first solution is
x= 5

and the second is

x = -3

2007-10-08 07:10:37 · answer #2 · answered by Teah 1 · 0 0

X(squared) - 2x = 15
=> X(squared) - 2x - 15 = 0
=> (x - 5 )( x+ 3) = 0
=>x = 5 OR x = -3

2007-10-08 06:52:48 · answer #3 · answered by harry m 6 · 0 0

x^2 - 2x - 15 = 0

x^2 - 2x + 1 - 1 - 15 = 0

(x - 1)^2 - 16 = 0

(x - 1)^4 - 4^2 = 0

(x - 1 - 4)(x - 1 + 4) = 0

(x - 5)(x + 3) = 0

x1 = 5
x2 = -3

2007-10-08 06:57:14 · answer #4 · answered by Amit Y 5 · 0 0

x=5. 5^2 - 2(5) = 15

2007-10-08 06:53:19 · answer #5 · answered by mark c 1 · 0 0

This is simple : first balance it out so all the variables and constants are on one side. X^2 - 2x - 15 = 0. Equate to 0.
(X +3)(X-5)
Roots are {-3,5}

2007-10-08 07:04:32 · answer #6 · answered by TicToc.... 7 · 0 0

x^2 - 2x = 15
x^2 - 2x - 15 = 0

15 = 3* 5
(3 - 5) = -2

(x - 5) ( x + 3 ) = x^2 + 3x -5x -15 = x^2 - 2x -15 = 0

x^2 - 2x = 15

2007-10-08 07:04:11 · answer #7 · answered by Eduardo (lalo) Leal 2 · 0 0

if x square-2x=15
x square-2x-15=0
x square-5x+3x-15=0
x (x-5)+3(x-5)=0
(x-3)(x-5)=0
ans x=3 or x=5

2007-10-08 06:55:26 · answer #8 · answered by $jess$ 4 · 0 0

x ² - 2 x - 15 = 0
( x - 5 ) ( x + 3 ) = 0
x = 5 , x = - 3
You make me feel better---I have these days too!

2007-10-11 07:51:16 · answer #9 · answered by Como 7 · 0 0

(x-5)(x+3)

2007-10-08 06:56:51 · answer #10 · answered by xandyone 5 · 0 0

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