Help with Physics HW?

Question

An adventurous archaeologist crosses between two rock cliffs, with a raging river far below, by slowly going hand-over-hand along a rope stretched between the cliffs. He stops to rest at the middle of the rope. The rope will break if the tension in it exceeds 2.50 x 10^4 N, & his mass is 90 kg.

(a) If the angle theta is 10.0°, find the tension in the rope.

(b) What is the smallest value the angle can have if the rope is not to break?

Answer 1

The vertical weight of the climber is split between the rope and sin(th)

As Tension*sin(th)=.5*m*g


a) th=10
Tension =2540 N

b) asin((90*9.8)/(2*25000))
or 1 degree

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