please help me with this algebra 2 problem?

Question

what is the range of the function f ( x ) = xsquared + 4 when the domain is (-2, 5, 7 )?? please help me by clearly stating the steps. thanks!!!!!!!!

Answer 1

plug -2, 5, and 7 all into the original function and you should get 3 outputs...those 3 are the range...it should be 8, 29, 53...i think...that was a long time ago

edit: do not subtract like below...that is the range for the entire set...your looking for the 3 like above.

Answer 2

Range is the values that a function can take given a domain for its 'x' or object value.

In our case,
f ( x ) = xsquared + 4 and domain is (-2, 5, 7 ).

So, we just need to evaluate f(x) at x =-2,5 and 7. Indeed,

f (-2 ) = (-2)squared + 4 = 4 + 4 = 8

f (5 ) = (5)squared + 4 = 25 + 4 = 29

f (7 ) = (7)squared + 4 = 49 + 4 = 53

So the answer is : For the domain (-2, 5, 7 ), the range of our function or equivalently the value of 'f(x)' at these 'x values' is
(8, 29, 53)

Anothe way to put it is :

x = (-2, 5, 7 ) yields f(x) = (8, 29, 53)

Where 'x ' is called the 'object' while its associated value or
'f(x)' is called the 'range'

Hope this helped.

:)

Answer 3

i'm trying to think back several years ago, but i would say it is the following:

using all 3 domain values of x in the function, you get the following numbers: 8, 29 and 53. the range of the function is the greatest number minus the least. So 53-8 = the range, or 45

Answer 4

plug the (-2,5,7) into where an x is then solve.

1. f(-2)=-2(sqaured)+4
f(-2)=4+4
f(-2)=8

2. f(5)=5(sqaured)+4
f(5)=25+4
f(5)=29

3. f(7)=7(sqaured)+4
f(7)=49+4
f(7)=53
So your range is 53-8=45

Answer 5

Plugging in the values yields {8,29,53} and the minus sign is of no consequence since the square of a negative number is always positive.

Answer 6

I don't know

Answer 7

x____- 2____5____7
f(x)___8___29___53-------- is the range.