The given point (-2,9) lies on the graph that is symmetric about x-axis, y-axis, and origin. State the other points that must also lie on the graph
2007-10-08 06:32:37 · 7 answers · asked by referencearea 2 in Science & Mathematics ➔ Mathematics
(2,9), (-2,-9), and (2,-9).
2007-10-08 06:37:36 · answer #1 · answered by Amelia 6 · 0⤊ 0⤋
I'll give you a hint so you can complete the problem. That way you will have to think and you will learn something. The point (1,3) is found by going one unit right from the origin and then 3 unjits up . A symmetric point about the x axis is 1 unit right of the orgin and 3 units down to (1,-3). The symmetric point about the y-axis would be one unit left from the origin and then 3 units up to (-1,3). The symmetric point of (1,3) about the origin is found on a line from (1,3) passing through the origin. So go 1 unit left from origin and then 3 units down to (-1,-3). These points are also called the reflections of (1,3) about the x-axix, y-axis, and origin. Now draw a graph and locate (-2,9). Now find the reflections of this point about the x-axis, y-axis, and origin asa was done above.
2007-10-08 13:45:33 · answer #2 · answered by baja_tom 4 · 0⤊ 0⤋
If it is symmetrical I would expect other points to be mirror images of the given point. I would think that there is a (+2,9), (+2,-9), and (-2, -9) on the curve.
Am I a genius now? Would that make my geometry teacher a double genius?
2007-10-08 13:38:44 · answer #3 · answered by Rich Z 7 · 0⤊ 0⤋
We are given one point namely (-2,9) and are told that its 'symmetric' to certain 'axis'.
Just draw a sketch on a paper and you will better see the results below. I want to avoid using complicated equations and solutions.
(-2,9) symmetric to x - axis means the symmetrical point to this point is ( -2, -9 )
(-2,9) symmetric to y - axis means the symmetrical point to this point is ( 2, 9 )
(-2,9) symmetric to the origin ( 0,0 ) means the symmetrical point to this point is ( 2, -9 )
Regards,
:)
2007-10-08 13:40:23 · answer #4 · answered by jonny boy 3 · 0⤊ 0⤋
(-2, 9) symmetiric about the y axis is (2, 9)
(-2, 9) symmetiric about the x axis is (-2, -9)
(-2, 9) symmetiric about the origin is (2, -9) & (9, -2)
2007-10-08 13:39:45 · answer #5 · answered by Richard B 3 · 0⤊ 0⤋
(2, 9) (-2, -9) (2, -9)
1. Across X-axis < (x2, y2) = (-x1, y1)
2. Across Y-axis < (x2, y2) = (x1, -y1)
3. Across Origin < (x2, y2) = (-x1, -y1)
2007-10-08 13:41:47 · answer #6 · answered by Brandon E 2 · 0⤊ 0⤋
i think.(2,9),(2,-9),(-2,-9)
2007-10-08 13:38:25 · answer #7 · answered by $jess$ 4 · 0⤊ 0⤋