Find the size of the angle between the line 4x-5y=1 & the positive direction of the x axis?

Question

Have no idea how to do this and have a test tomorrow. Any help appreciated. Any website's appreciated :D.

Answer 1

4x - 5y = 1

5y = 4x - 1

y = 4/5 x - 1/5

slope = 4/5

the other line being x axis itself the angle theta between them

theta = tan^-1 (4/5)

tan theta = 4/5

theta = 38.7 degrees

Answer 2

you have accomplished each and every ingredient thoroughly so far ... the concern is that calculators for some mysterious reason supply recommendations as adverse angles contained in the 4th quadrant for adverse sines and tangents ... so it rather is rather imparting you with the perspective between the x-axis and the factor of the line decrease than the x-axis If the tan is adverse then the perspective the line makes with the functional path of the x-axis might have its terminal facet contained in the 2d quadrant in basic terms by means of certainty tan is likewise adverse contained in the 2d quadrant ... so which you like that attitude So all you may do to get the functional attitude with understand to the x-axis is upload the adverse answer the calculator supplies you to one hundred 80° so the needed attitude = one hundred 80 - 26.57 = 153.40 3°

Answer 3

rearrange the equation so you get x=....

x=0.25+1.25y

plot this line on a graph (the number in front of the "y" is the gradient and the 0.25 is where it crosses the "y" axis

if you rearrange it so you get y=....

y=0.8x - 0.2

so this will tell you where the line crosses the "x" axis (i.e. -0.2)

so now you can draw a right angled triange... with 0.25 vertical and 0.2 horizontal

then the angle....

tan (angle) = opposite / adjaicent
tan (angle) = 0.25 / 0.2
tan (angle) = 1.25
angle = 51 deg

Answer 4

5y = 4x - 1
y = (4/5) x - 1 / 5
Let θ = required angle
tan θ = 4/5
θ = 38.7 °

Answer 5

Should have stayed alert in class.