can someone help me with chemistry?

0 ⤊

If 500 grams of water at 25 degrees Celsius loses 10500 joules of heat, what will be the final temperature of the water?

2007-10-08 05:30:04 · 2 answers · asked by Lannymac 2 in Science & Mathematics ➔ Chemistry

show your work please

2007-10-08 05:32:06 · update #1

Specific heat of water = 4.18 J
q = grams x specific heat ( delta T)
10500 = 500 x 4.18 ( 25- T)
10500 = 2090 ( 25- T)
5.02 = 25 - T
T = 19.98 °C

2007-10-08 05:39:31 · answer #1 · answered by Dr.A 7 · 0⤊ 0⤋

Luke warm.

2007-10-08 05:31:59 · answer #2 · answered by Fuzzybutt 7 · 0⤊ 2⤋