2007-10-08 05:25:49 · 6 answers · asked by rainwater 3 in Science & Mathematics ➔ Mathematics
There is no such thing as an 8 foot Pole. If there were they would have the world's best basketball team
2007-10-08 05:29:23 · answer #1 · answered by wowser 5 · 0⤊ 2⤋
There r a lot of variables on that question.
Lets say it is a pole with a shadow of 12 feet. Then lets say that it is at the same time. That would mean that the pole is simply 4 times larger, so
8x4= 32 feet tall.
But if its a different time, or it says the width of the tree at the top, then this is wrong. This is the best i can help u.
2007-10-08 12:31:59 · answer #2 · answered by TheOtherDoomGuy 5 · 1⤊ 0⤋
8/x = 3/12
8 * 12/3 = x
x = 32
Tree would be 32 feet tall
2007-10-08 12:30:43 · answer #3 · answered by PeterT 5 · 1⤊ 0⤋
Think of it as a ratio.
8/3 = x/12
3 * 4 = 12.
Therefore 8 * 4 = x
x = 32 ft.
2007-10-08 12:36:30 · answer #4 · answered by oldtimer 2 · 0⤊ 0⤋
8/3 = x/12
cross multiply
3x=96
x= 32 feet tree is 32 feet tall
2007-10-08 12:29:40 · answer #5 · answered by puurplemooose 6 · 1⤊ 0⤋
tan θ = 8 / 3
let height of tree = h
tan θ = h / 12
h = 12 tan θ
h = 12 x 8 / 3
h = 32 ft
OR
8/3 = h/12
h = 96/3
h = 32 ft
2007-10-08 14:51:50 · answer #6 · answered by Como 7 · 1⤊ 0⤋