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A mixture of KClO3 and KCl with a mass of 0.915 g was heated to produce O2. After heating, the mass of residue was 0.614 g. Assuming all the KClO3 decomposed to KCl and O2, calculate the mass percent of KClO3 in the original mixture.
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2007-10-08 05:20:10 · 2 answers · asked by bumblebee 4 in Science & Mathematics Chemistry

2 answers

REMEMBER: ALL COMPARISONS ARE DONE IN MOLES
Find mass of oxygen evolved (.915-.614g)=mE
Find MOLES of oxygen evolved= mE/32
Find Moles of KClO3 that provide mE/32 moles:
2 KClO3 = 3O2 + 2 KCl.
So KClO3 moles= (2/3)*(mE/32)=MKO
Find mass of KClO3 corresponding to above= (mol wt KClO3)*MKO
Find mass percent KClO3 in reactant
100*(mol wt)*MKO/0.915 gm

2007-10-08 05:35:46 · answer #1 · answered by cattbarf 7 · 0 0

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2016-10-21 11:12:47 · answer #2 · answered by Anonymous · 0 0

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