Derivative of a function?

Question

Find the derivative function of:
f(x) = (4x^2-5)^4

This is what I've done so far:

4(4x^2-5)(8x)=

f'(x)=4(32x^3-5)

Can someone check to see if I'm right?

Answer 1

Not quite. You lost an exponent somewhere.

The first step should be

4(4x^2 - 5)^3 (8x)

which simplifies to

32x (4x^2 - 5)^3

Answer 2

Close.

You wrote 4(4x^2-5)(8x). But you don't drop the power of the binomial, only reduce it. So it should be 4(8x)(4x^2-5)^3. When you expand it you get 4(8x)(64x^6 - 240x^4 - 300 x^2 - 125) = 2048x^7 - 7680x^5 - 9600x^3 - 4000x

Answer 3

Sorry, I disagree.

f'(x) = [4(4x^2-5)^3](8x)

Answer 4

You drop the y because of the fact the slope of 7x is 7 The operation is addition so which you upload the derivatives, so which you will possibly locate the spinoff of 7y and upload it to the spinoff of others. Given a linear equation y=6x, what's the slope? what's a spinoff? a spinoff is the slope of a component, however the function is LINEAR, so that's no longer suitable what the component is, its only the slope. it rather is likewise the explanation in the back of the spinoff of constants as 0. y=6 The function is linear. Slope=0 spinoff=comparable difficulty, 0

Answer 5

You missed only one thing
the right answer is
f'(x) = 4(4x^2-5)^3(8x)

Answer 6

f `(x) = 4 (4 x ² - 5) ³ ( 8x )
f `(x) = ( 32 x ) ( 4 x ² - 5 ) ³
OR
let y = (4x² - 5)^4
let u = 4x² - 5
y = u^4
dy/du = 4u³
du/dx = 8x
dy/dx = (dy/du) (du/dx)
dy/dx = 4 u ³ (8x)
dy/dx = (32 x) (4 x ² - 5) ³

Your answer is incorrect but hopefully you can follow above methods of solution.

Answer 7

f(x) = (4x^2-5)^4
f'(x)=4(4x^2-5)^3(8x)
=32x(4x^2-5)^3