2007-10-08 00:30:56 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sin(A-B) = sinAcosB - cosAsinB
sin90˚ = 1
cos90˚ = 0
sin(90˚-X)
= sin90˚cos(X) - cos90˚sin(X)
= 1*cos(X) - 0*sin(X)
= cos(X)
2007-10-08 00:35:26 · answer #1 · answered by gudspeling 7 · 5⤊ 0⤋
Sin X-90
2016-12-26 08:46:06 · answer #2 · answered by mcglamery 3 · 0⤊ 0⤋
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RE:
what does sin(90-X) equal? is it cosX or like -sinX?
2015-08-10 07:17:02 · answer #3 · answered by Shay 1 · 0⤊ 0⤋
sin 90° cos x - cos 90° sin x
(1) cosx - 0
cos x
2007-10-08 04:37:55 · answer #4 · answered by Como 7 · 1⤊ 0⤋
Sin 90-x
2016-09-30 00:40:01 · answer #5 · answered by Anonymous · 0⤊ 0⤋
sin(A+B) =sinA.Cosb + cosA.SinB
=sin(90).Cos(-X) + Cos 90.Sin(-X)
=cosX + 0.Sin(-X) =cosX
note A =90
B = -X
2007-10-08 00:36:32 · answer #6 · answered by cooldude_raj07 2 · 0⤊ 0⤋
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Do you mean f(x) = (sinx - 1) / cosx ? Use the quotent rule. f ' (x) = [cosx(cosx - 0) - (sinx - 1)(-sinx)] / cos^2 x f ' (x) = [cos^2 x + sin^2 x - sinx] / cos^2 x f ' (x) = [1 - sinx] / cos^2 x
2016-03-26 22:25:24 · answer #7 · answered by Janet 4 · 0⤊ 0⤋
it is equal to cos (X)
and also Cos(90-X) = Sin X
2007-10-08 00:36:39 · answer #8 · answered by prabhaswin 1 · 1⤊ 0⤋
cosx/-sinx
2016-03-18 02:57:07 · answer #9 · answered by Marie 4 · 0⤊ 0⤋
it is definitely cosx as the angle would be within the first quadrant
2007-10-08 00:36:09 · answer #10 · answered by Sagar 2 · 0⤊ 0⤋