very, VERY hard math question?

Question

can someone give me this very hard questions answer?

(9 raised to the power of 62773 + 2) raised to the power of 83721

it may look like this:

(9 62773 + 2) 83721

since they are squares, they should be small.

Answer 1

That's a very very very very big number. More than there are atoms in the universe.

Answer 2

It is not possible to answer your question as asked.

This question has been asked twice earlier but with a difference. The answer desired in earlier questions had been that the sum of digits in the answer till it is a single digit.
Someone successfully answered the question and to the best of my memory answer was 8.
It was like this.
9^62773 will have digits adding up to 9
9 + 2 = 11
1 + 1 = 2
Now,
2^0 = 1
2^1 = 2
2^2 =4
2^3 = 8
2^4 = 16 => 1 + 6 = 7
2^5 = 32 => 3 + 2 = 5
2^6 = 64 => 6 + 4 = 10 => 1 + 0 = 1
Thereafter, these numbers keep on repeating.

Now, 2^83718 => sum of digits corresponding to 2^0 = 1
So 2^83721 => sum of digits corresponding to s^3 = 8.

Answer 3

Looks like a Log problem at least that is what I think it is to show how extremely large numbers can be worked using logs.

(log9^ 62773 +2)^83721

59902.665045 * 83721= 5015111020.24= 5.02 x 10^9

or

log 59902.665*83721= 3.9997 x 10^5

Answer 4

what is the question?
what sould you do with that "small" number?