solve for the following equation for x 3^x=27
2007-10-07 19:02:22 · 10 answers · asked by jose u 1 in Science & Mathematics ➔ Mathematics
x=3
3^3=27
2007-10-07 19:04:15 · answer #1 · answered by Master Maverick 6 · 1⤊ 0⤋
x = 3
3 * 3 * 3 = 27
2007-10-08 02:04:50 · answer #2 · answered by The Monkey's Paw 2 · 0⤊ 0⤋
Method 1
3^x = 27
x = 3
Method 2
Take log base 3 of both sides
x log 3 = log 27
x = 3
2007-10-10 14:28:48 · answer #3 · answered by Como 7 · 0⤊ 0⤋
3 to the 3rd power - 3x3x3=27
2007-10-08 02:04:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋
answer=3
2007-10-08 02:04:46 · answer #5 · answered by Christina 5 · 0⤊ 0⤋
either with common knowledge of powers
3^1 = 3
3^2 = 9
3^3 = 27
or with logs
log3^x = log27
xlog3 = log27
x = log27 / log 3
x = 3
2007-10-08 02:06:53 · answer #6 · answered by Anonymous · 0⤊ 0⤋
3^x = 27
(3)(3)(3) = 27
proof... (3)(3)=9 (9)(3)=27
x = 3
2007-10-08 02:11:54 · answer #7 · answered by -^Chris^- 3 · 0⤊ 0⤋
the answer is 3.
2007-10-08 02:06:21 · answer #8 · answered by ivan 2 · 0⤊ 0⤋
3^x = 27
or 3^x = 3^3
comparing both sides
we get
x = 3 ans.
2007-10-08 02:06:07 · answer #9 · answered by shailesh 2 · 0⤊ 0⤋
3^x=27
lg(3^x)=lg27
xlg3=lg27
x=lg27/lg3
x=3#
2007-10-08 02:14:24 · answer #10 · answered by jackleynpoll 3 · 0⤊ 0⤋