The equilibrium constant for the reaction:
H2 + I2 = 2HI
has a value of 50.0 at 745K.
When 1 mol I2 and 3 mol H2 are allowed to come to equilibrium at 745K in a flask of volume 10L, what amount in moles of HI will be produced?
2007-10-07 17:46:25 · 2 answers · asked by Peter G 3 in Science & Mathematics ➔ Chemistry
Since volume is a constant and pressure is a constant, the number of moles is directly proportional to the concentration. We may directly use the number of moles as the concentration
.............H2 + I2 = 2HI
Initially: 3.......1......0
3-x 1-x 2x
(2x)^2/(3-x)(1-x) = 50
4x^2 = 50(3 - 4x + x^2)
2x^2 = 25(3 - 4x + x^2)
23x^2 -100x + 75 = 0
x1= 3.38, x2 = 0.96
Ignore x1 (do you know why?), we know 2x = 1.9 (mole of HI produced)
2007-10-07 18:48:43 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋
2I5
2007-10-08 01:10:53 · answer #2 · answered by Tim O 5 · 0⤊ 0⤋