Identify the center and the radius of the circle with equation (x - 6)2 + y2 = 49.?

Question

Identify the center and the radius of the circle with equation (x - 6)2 + y2 = 49.

center (0, -6) and radius = 7

center (0, 6) and radius = 49

center (-6, 0) and radius = 7

center (6, 0) and radius = 7

Answer 1

the center can be found at (h,k), where h is whatever is subtracted from the x and k is whatever is subtracted from the y. The radius is the square root of the number after the = sign.

Answer 2

(x - a)^2 + (y - b)^2 = r^2
has center at (a, b)
and radius r