What is the direction in degrees of the resultant of two concurrent forces, 40.0 N and 35.0 N, exerted at an angle of 120. degrees between the forces?
2007-10-07 16:55:21 · 2 answers · asked by jetengine767 3 in Education & Reference ➔ Homework Help
Suppose the 40N force is in the positive x direction, and the 35N force is directed 120 degrees counterclockwise from the positive x axis.
Then:
x = 40 + 35cos120
x = 22.5N
y = 35sin120
y = 30.31N
Resultant = √(22.5^2 +30.31^2) = 37.75N
Angle = arctan(30.31/22.5) = 53.41degrees counterclockwise from the positive x axis.
Since we imposed the reference system for the convenience of the solution, we should state the angle more generally as:
53.41degrees measured from the 40N force toward the 35N force
2007-10-08 00:02:48 · answer #1 · answered by jsardi56 7 · 0⤊ 0⤋
im pretty sure u have to add 40 and 35 together so 75.0 N
2007-10-08 00:00:32 · answer #2 · answered by ybnimako 2 · 0⤊ 1⤋