Math help!!! =]?

Question

I neeed help with these problems. im sorta stuck.

Simplify the expressions....

square root of 3 X square root of 27

square root of 18 X square root of 12

square root of 4 X square root of 63

square root of 1/16


square root of 9/25



thanks! =]

Answer 1

square root of 3 X square root of 27 =
square root of 81 = 9

square root of 18 X square root of 12 =
square root of 216 = square root of 36 times square root of 6 = 6 radical 6

square root of 4 X square root of 63 =
square root of 252 = square root 36 times square root 7 =
6 radical 7

square root of 1/16 = 1/4


square root of 9/25 = 3/5

Answer 2

√3 x √27 = √3 x ( √3 x √9 ) = 3 x 3 = 9

√18 x √12 = ( √2 x √9 ) x (√3 x √4) = 6√6

√4 x √63 = √4 x ( √9 x √7) = 6√7

√(1/16) = √1 / √16 = 1/4

√(9/25) = √9 / √25 = 3/5

Answer 3

Why can't finih these dear, r U a little girl??

square root of 3 X square root of 27
3^1/2 x 3^1.5 = 3^2 = 9

square root of 18 X square root of 12
3 . 2^1/2 x 2 . 3^1/2 = 6^1.5

square root of 1/16 = 1/4

square root of 9/25 = 3/5



square root of 4 X square root of 63
2 x 3x7^1/2 = 6x7^1/2

Answer 4

sq rt(3)Xsq rt(27)
=sq rt(3*27)
=sq rt(81)
=sq rt(9^2)
=9
TRY OTHERS ON THE SAME LINES.

Answer 5

1. Sq rt of 3xSq rt of 27 ;
or sq rt of 3x sqrt of 3x sq rt of 9 ;
or = 3x3 =9.

2. Sq rt of 18 x sq rt of 12;
or (sq rt of 2x9) x (sq rt of 4x3);
or (3xSq rt of 2 )X (2x sq rt of 3)
or 6x sq rt of 6.


3. Sq rt of 4x sq rt of 63 ;
or 2 x ( sq rt of 7x9)
or 6 x sq rt of 7.

4. Sq rt of 1/16 ;
or 1/4.

5. Sq rt of 9/25 ;

or =3/5