Help with algebra: x^2+4y^2=0?

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find all pairs (x,y) (for x and y both real real numbers) satisfying the equation.

2007-10-07 16:05:59 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

(0,0)

2007-10-07 16:10:18 · answer #1 · answered by ali 6 · 1⤊ 0⤋

x=0 y=0 are the only real numbers

2007-10-07 23:20:07 · answer #2 · answered by Marko G 1 · 0⤊ 0⤋

Answer is : empty set.

Note x^2 = -4y^2, but if x, y are in R, then this can not happen,
since x^2 is positive, so is y^2.

2007-10-07 23:09:37 · answer #3 · answered by pbb1001 5 · 0⤊ 0⤋

hmm, simplified is x=2yi, (i is sqrt -1)

2007-10-07 23:10:48 · answer #4 · answered by ttotheimmyy 1 · 0⤊ 0⤋