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A rock is thrown vertically upward with a speed of 12.0 from the roof of a building that is 70.0 above the ground. Assume free fall.
Part A
In how many seconds after being thrown does the rock strike the ground?



Part B
What is the speed of the rock just before it strikes the ground?

2007-10-07 15:59:15 · 1 answers · asked by Mallory 1 in Science & Mathematics Physics

1 answers

Maximum height
ymax = 70 + sqrt(v0^2/(2g))
Time to max height
t1 = v0/g
Time from max height to landing
t2 = sqrt(2ymax/g)
A. Total time t = t1 + t2
B. v = sqrt(2g*ymax)

2007-10-08 04:51:27 · answer #1 · answered by kirchwey 7 · 0 0

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