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Let f(x) = -2 x^{5} \sqrt{x} + \frac{-6} {x^{2} \sqrt{x} } f'(x) equals what?

2007-10-07 15:42:38 · 1 answers · asked by pwayballa11 1 in Science & Mathematics ➔ Mathematics

1 answers

f(x) = -2x⁵√x + -6/(x²√x) = -2x^(11/2) - 6x^(-5/2)
f'(x) = -11x^(9/2) + 15x^(-7/2)

2007-10-07 15:53:00 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋

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