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2007-10-07 15:38:08 · 1 answers · asked by pwayballa11 1 in Science & Mathematics Mathematics

1 answers

f'(x) = x^4 - 2e^x cos (x) + 2e^x sin(x)

f'(-1) = 1 - 2e^(-1) cos(-1) + 2e^(-1) sin (-1)

= 1 - 2cos(-1)/e + 2sin(-1)/e

= (e - 2cos(-1) + 2sin(-1))/e

2007-10-07 15:43:27 · answer #1 · answered by jenh42002 7 · 0 0

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