CAn someone go through the steps to solve this problem?;?

Question

Simplify:

Sec x - Sin x Tan x

Answer 1

Very easy mate, see the master:
Sec x - Sin x Tan x
1/cosx - sin x . sinx/cosx
1/cosx-sin^2/cosx
1-sin^2/cosx
cos^2/cosx = cosx

Answer 2

sec x = 1/cos x while tanx = sin x/cos x, so you will have:

1/cos x - sin x(sin x/cos x)
1/cos x - sin^2 x/cos x

1 - sin^2 x/cos x: 1 - sin^2 x is equal to cos^2 x, then:

cos^2 x/cos x; simplifying:

cos x

Answer 3

Sec x - Sin x Tan x

1/cox x - sin x sin x/cos x

(1 - sin^ x)/cos x

cos^ x/cos x

cos x

Answer 4

sec(x) =1/cos(x)
tan(x) = sin(x)/cos(x)

sec(x) - sin(x) * tan(x) =
1/cos(x) - sin(x) * sin(x)/cos(x) =
(1 - sin^2(x))/cos(x)

from the trig identity cos^2(x)+sin^2(x) = 1
we get cos^2(x) = 1 - sin^2(x)

substitute this in to get cos^2(x)/cos(x) = cos(x)

Answer 5

sec(x) = 1/cos(x)
tan(x) = sin(x)/cos(x)

so you have

1/cos(x) - sin^2(x)/cos(x)
(1-sin^2(x))/cos(x) by Pythagorean identity (sin^2(x)+cos^2(x)=1)
cos^2(x)/cos(x)
cos(x) -