x=-b+/-sqrt(b^2-4ac)/2a (quadratic formula)
=17+/-sqrt(17^2-4(6)(-14))/12
=17+/-sqrt(625)/12
=17+/-25/12
=42/12,-8/12
=7/2,-2/3
2007-10-07 14:41:44
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answer #1
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answered by slick_licker88 3
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First we see that this is a quadratic equation. There are 2 angles to solve a quadratic equation.
1. factoring: if the factors are obvious this is the way to go.
Example:
x^2 -3x + 2 = 0
We can factor this to:
(x - 2)(x - 1) = 0 and the zeros are 2 and 1.
2. The Quadratic Formula: This method will get you the zeros of any quadratic equation, but it is a bit more tedious, so you should factor if the factors are obvious. In this case the factors aren't obvious. Here is te quadratic formula:
the values of x for which ax^2 + bx + c = 0 are:
(-b +/- (b^2 - 4ac)^(1/2))/2a
Plugging your values in we get
(17 +/- ((-17)^2 - 4*6*(-14))^(1/2))/2(6) =
(17 +/- (289 - (-336)^(1/2))/12 =
(17 +/-(625)^(1/2))/12 =
(17 +/- 25)/12
= 42/12 = 7/2 and -8/12 = -2/3
2007-10-07 15:08:28
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answer #2
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answered by Anonymous
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The working formulation for this project is Distance = velocity * Time With the 25 mph tailwind, D = (A + 25)(4) --- call this Equation a million the place A = plane velocity in nevertheless air and by the return holiday with the comparable wind, D = (A - 25)(5) --- call this Equation 2 with the aid of fact the D's in the two Equation a million and Equation 2 are the comparable, then Equation a million = Equation 2. This being pronounced, (A + 25)(4) = (A - 25)(5) Simplifying, 4A + one hundred = 5A - a hundred twenty five Combining words, 5A - 4A = a hundred twenty five + one hundred = 225 A = 225 mph
2016-10-10 12:21:07
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answer #3
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answered by ? 4
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Hey there!
Use grouping to factor the problem.
6x^2-17x-14=0 --> Write the problem.
6x^2-21x+4x-14=0 --> Rewrite -17x as -21x+4x.
3x(2x-7)+2(2x-7)=0 --> Factor out 3x from 6x^2-21 and factor out 2 in 4x-14.
(2x-7)(3x+2)=0 --> Factor out 3x+2.
2x-7=0 or 3x+2=0 --> Apply the property if pq=0, then p=0 or q=0.
x=7/2 or x=-2/3 Solve each equation for x.
So x=-2/3 or x=7/2, or {-2/3,7/2}.
Hope it helps!
2007-10-07 15:16:51
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answer #4
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answered by ? 6
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x = [ 17 ± √(289 + 336) ] / 12
x = [17 ± √(625) ] / 12
x = [17 ± 25 ] / 12
x = 42 / 12 , x = - 8 / 12
x = 21 / 6 , x = - 2 / 3
x = 3½ , x = - 2 / 3
2007-10-07 21:06:20
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answer #5
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answered by Como 7
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This is of the form ax^2+bx+c=0
x=[-b+-sqrt(b^2-4ac)]/2a
a=1 b=-17 c=-14
x=-(-17)+sqrt( (-17)(-17) - 4(1)(-14) ) /2
=[17+sqrt(289+96)]/2
and [17-sqrt(289+96)]/2
x=3.5 and -0.667
2007-10-07 14:46:50
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answer #6
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answered by cidyah 7
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6x^2 - 17x -14 = 0
6x^2 - 21x + 4x - 14 = 0
(6x^2-21x) + (4x-14) = 0
3x(2x-7) + 2(2x-7) = 0
(3x+2)(2x-7) = 0
3x + 2 = 0
x = -2/3
2x - 7 = 0
x = 3.5
2007-10-07 14:42:00
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answer #7
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answered by UnknownD 6
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