If you have a bag that has 4 red marbles, 6 blue, and 5 green. If someone takes out one marble and doesnt replace it and picks out anothjer one what is the probablilty that you can pull out a green one first and then a blue one? how do you do this problem? Thanks in Advance!!
2007-10-07 13:48:56 · 3 answers · asked by Brittany l 2 in Science & Mathematics ➔ Mathematics
the probability of getting the first green marble is 5/15
since there are no replacement, there are 14 marbles left, out of which 6 are blue. So the probability of piking a blue marble is 6/14
P = 5/15 * 6/14
P = 1/7 <== answer
2007-10-07 14:03:26 · answer #1 · answered by 7 · 0⤊ 0⤋
The answer should be all the green marbles(5) over the total marbles(15) times(x) all the blue marbles(6) over one less the total marbles(14) because you took one marble out without putting it back. 5/15 x 6/14 = 30/210 simplified = 1/7
2007-10-07 21:10:42 · answer #2 · answered by dancing tinkerbell 2 · 0⤊ 0⤋
(5 (number of green ones)/15 (total))*(6 (number of blue ones)/ 14(total))
2007-10-07 20:56:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋