What 4.0 M HCl is required to react completely with 3.00 g magnesium?

Question

When hydrochloric acid reacts with magnesium metal, hydrogen gas and aqueous magnesium chloride are produced. What volume of 4.0 M HCl is required to react completely with 3.00 g of magnesium

Answer 1

The atomic mass of magnesium is: 24.305 g/Mol
3.00g Mg <==> 3.00/24.305 = 0.123 Mol Mg
Mg + 2HCl ---> MgCl2 + H2
0.123*2/4.0 = 0.62 L
More than 0.62L of 4.0 M HCl is required to react completely with 3.00 g magnesium.

Answer 2

Na2CO3 + 2 HCl ---------------> 2 NaCl + CO2 + H2O 2 moles of HCl react with a million mole of Na2CO3 10.0g/one 0 5.ninety 9 g/mole = 0.0943 moles Na2CO3............molar mass of Na2CO3 =one 0 5.ninety 9 g/mole moles HCl= 0.094 x 2= 0.188 moles molarity = mole/L 0.188 moles/3 moles /L=0.0627 L =sixty 2.7 ml