The perimeter of a triangle is 147cm. if the sides are consecutive odd integers, find the length of each side.
2007-10-07 12:59:05 · 8 answers · asked by hammy 3 in Science & Mathematics ➔ Mathematics
x = odd integer 1
x + (x+2) + (x+4) = 147
3x + 6 = 147
3x = 141
x = 47
47, 49, 51
2007-10-07 13:03:23 · answer #1 · answered by meego99 2 · 1⤊ 0⤋
If the sides are consecutive odd integers, this means that the sides have the following lengths (we'll call the sides A, B, and C)
A: s
B: s-2
C: s-4
Now, add up the lengths of A, B, and C.
You get
3s - 6 which equals 147.
Add 6 to both sides.
You get 3s = 153
153/3 = 51 = s
So in conclusion,
Side A = 51
Side B = 49
Side C = 47
Add the sides up and TADA! They equal 147!
:-)
2007-10-07 13:09:39 · answer #2 · answered by Teah 1 · 0⤊ 0⤋
Consecutive odd integers would be represented as x, x + 2, and x + 4. Add them together and you get 3x + 6 which is set equal to 147 cm.
3x + 6 - 6 = 147 - 6
3x = 141
x = 47
x + 2 = 49
x + 4 = 51
51 + 49 + 47 = 147
2007-10-07 13:03:47 · answer #3 · answered by Howard H 7 · 0⤊ 0⤋
Solve the equation x + (x+2)+(x+4)=147.
Then x = 47.
The sides are thus 47, 49, 51.
2007-10-07 13:06:01 · answer #4 · answered by ? 3 · 0⤊ 0⤋
The sides are s-2, s, s+2
Those add to 3s
147/3s = 49
So the three sides are
47, 49, 51
2007-10-07 13:02:20 · answer #5 · answered by Steve A 7 · 0⤊ 0⤋
147/3 = 49
therefore answer is 47, 49, 51
2007-10-07 13:03:21 · answer #6 · answered by Anonymous · 0⤊ 0⤋
s+1
s+3
s+5
3s+9=147
3s=138
s=46
47, 49, 51
2007-10-07 13:06:27 · answer #7 · answered by Madelyn 2 · 0⤊ 0⤋
s+(s+2)+(s+4)=147
3s+6=147
-6 -6
3s=141
/3 /3
s=47
Sides are
47
49
51
I got this kind of homework assigned this weekend!
2007-10-07 13:43:48 · answer #8 · answered by Michelle Z 3 · 0⤊ 0⤋