Information is given about a complex polynomial f(x) whose coefficients are real numbers. Find the remaining zeros of f(x): the degree of f(x) is 3, and it has 4 and 1 - i as zeros.
I'm utterly confused on how to do this. Please explain. Thank you.
2007-10-07 12:52:57 · 3 answers · asked by labelapark 6 in Science & Mathematics ➔ Mathematics
Third order polys with real coeff have at least one real zero. You're given that one.
If it has a complex zero then the complex conjugate of that zero is also a zero.
So, the third zero is 1+i, which is the complex conjugate of 1-i.
2007-10-07 12:58:42 · answer #1 · answered by modulo_function 7 · 0⤊ 0⤋
I think the other root should be 1 + i
so the three roots are 4, (1-i) and (1+i)
and the polynomial is p(x) = (x-4)(x-1-i)(x-1+i)
2007-10-07 20:02:49 · answer #2 · answered by norman 7 · 0⤊ 0⤋
1+i 3,4
2007-10-07 19:58:23 · answer #3 · answered by programhelp 2 · 0⤊ 1⤋