divide 350 by 6, its ~`55, so pick
45,50,55,60,65,70
which sum to 50x3 + 65x3 = 115x3 = 345
2007-10-07 12:18:15
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answer #1
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answered by vlee1225 6
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6 x a multiple of 5 must equal a multiple of 5, as you havent said whether it include those two numbers, ill assume it doesnt, so the only other multiple of 5 is 345.
firstly get the average of the sequence
345/5 = 57.5
as this is the middle number of the sequence then there are 3 above and below it, from the nearest multiple of 5, which are 55 and 60, so the whole sequnce will read 45,50,55,60,65,70.
these numbers added up = 345.
2007-10-07 19:22:14
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answer #2
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answered by becky c 2
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45+50+55+60+65+70
2007-10-07 19:24:36
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answer #3
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answered by glendiva1968 3
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x +x +5 +x+10+x+15+x+20 + x+25 =345
6x+ 75 =345
6x = 270
x = 45
Numbers are 45, 50, 55, 60, 65, 70
2007-10-07 19:27:13
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answer #4
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answered by ironduke8159 7
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345/6 = 57.5
So you want 6 multiples of 5 that average roughly 57-58.
We can use 3 multiples less than 58 and 3 greater than 58.
45, 50, 55, 60, 65, 70
(sum = 345)
2007-10-07 19:18:32
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answer #5
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answered by Jennifer Y 1
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