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How do you calculate the frequency of light when you're given the wavelength but not the speed? I know the equation for frequency is speed divided by wavelength, so I don't see how to do it without the speed part :P

Any help earns my undying love, I'm getting desperate. :D

2007-10-07 10:59:37 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

NO WAY. Dude. Dumb fuh-reaking moment.
Thanks for not being like 'stfudumbperson'
Have a best answer award. :D

2007-10-07 11:04:46 · update #1

4 answers

The speed is always the same! It's the speed of light, a constant so you can always work out the frequency if you are given the wavelength.

2007-10-07 11:03:28 · answer #1 · answered by Anonymous · 1 1

A useful property of light is that you ALWAYS know its speed. The speed of light is a universal constant, called "c".
c = 3.00*10^8 m/s

That should enable you to use the speed-frequency-wavelength equation more successfully.

2007-10-07 11:04:10 · answer #2 · answered by lithiumdeuteride 7 · 1 0

Photoelectric effect. By the way, this is what Einstein got his Nobel prize for sorting out. They never gave him one for relativity. Conservation of energy. Energy of light photon = threshold energy + k.e. of the electron (1) To find the energy of the light photon used, and of the threshold energy, use E = Planck's constant x frequency You know the threshold frequency. You still need to find the frequency of the light used, and you can get this from frequency x wavelength = speed of wave = c You can now use Eq. (1) to calculate k.e. I expect you know the formula for kinetic energy: k.e.= 1/2m v^2 Where in this case m is the mass of the electron and v is the speed you want to find. Care with units; since k.e. is in J, and v is in m s-1, m has to be in kg. Good luck!

2016-05-18 02:30:59 · answer #3 · answered by ? 3 · 0 0

speed of light is ALWAYS "[3.0 x 10^8 m/s]"

so if they give you wavelength.. you just take 3.0x10^8 and divide it by the wavelength..... you will get frequency

2007-10-07 11:04:35 · answer #4 · answered by J 3 · 0 0

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