trace the nested loops and output the final value of count?

Question

count =0;
for (i=1; i<5; i++)
for (j=1;j<=3; j++)

pls explain ur logic

Answer 1

your missing part of the program .

i, i<5 , i++ will execute 4 times
j, j<=3, j++ will execute 3 times
anything inside those if nested will happen 12 times
for each i , j loop will happen

Answer 2

5 * 3 = 15; and the logic is the simplest form of running time analyzing. The two dimensions of count gives the total running time.

But the answer could be O(1) for they are constant running time