The heat energy required to melt 1.00 g of ice at 0°C is 333 J. If one ice cube has a mass of 57.0 g, and a tray contains 16 ice cubes, what quantity of energy is required to melt a tray of ice cubes to form liquid water at 0°C?
2007-10-07 10:39:51 · 2 answers · asked by beeboroachgoingon197 1 in Science & Mathematics ➔ Chemistry
333 J will melt 1.00 g of ice.
So, 57.0 g x 333 J = 18,981.0 J...This will melt one ice cube.
Since there are 16 ice cubes, multiply 18,981.0 J by 16. That will give you 303,696.0 J. That will melt the whole tray of ice cubes. You're welcome.
2007-10-07 10:53:52 · answer #1 · answered by casale1216 2 · 0⤊ 0⤋
Multiply the number of ice cubes (16) times the mass of one ice cube (57.0 grams) Now you have total grams
Multiply that by 333 J / gram and you have the total joules
2007-10-07 17:48:06 · answer #2 · answered by reb1240 7 · 1⤊ 0⤋