Can someone please tell me what the oxidations numbers are for the following?
Cl in CCl4 H in NH3
P in P2O5 Na in Na3PO4
for Cl I got ....4
for P I got ..... 5
for H I got.... 1
for Na I'm getting 3.667 but it's not possible for decimal so would it be +1 ??
Please help? I have 30 min for this question... it's now 5:30 pm here so please help.
2007-10-07 10:31:38 · 2 answers · asked by Student 1 in Science & Mathematics ➔ Chemistry
Just for no confusion:
it's...
Cl in CCl4
H in NH3
P in P2O5
Na in Na3PO4
2007-10-07 10:32:26 · update #1
You are on the right track.
You have 4 chlorines, so th echarege on each one is -1
The charge on each H is +1
You are right about the P
The Na is +1
2007-10-07 10:51:01 · answer #1 · answered by reb1240 7 · 1⤊ 0⤋
oxidation of Cl = -1
H = +1
P = +5
Na = +1
2007-10-07 17:54:22 · answer #2 · answered by J 3 · 1⤊ 0⤋