8x / ( x^2 -121) feet
(x + 11) / 9x^3 feet
2007-10-07 10:13:47 · 6 answers · asked by mommawe'regoingtohell 1 in Science & Mathematics ➔ Mathematics
8x / ( x^2 -121) feet * (x + 11) / 9x^3 feet
= 8(x+11) /9x^2 ( x^2 -121)
= (8x + 88)/ (9x^4 - 1089x^4) Square feet
2007-10-07 10:18:26 · answer #1 · answered by Monah 3 · 0⤊ 0⤋
A=lw so...
A=(8x / (x^2-121)) * ((x+11) / 9x^3)
simplify L...
L= 8x/(x+11)(x-11)
and W is in simplest form so...
A= (8x / (x+11)(x-11)) * ((x+11) / 9x^3)
x+11 in denominator of L and x+11in numerator of W cancel
x in numerator of L reduces x^3 in denominator of W to x^2
giving us...
A= (8 / (x-11)) * (1 / 9x^2)
multiply and get...
A= 8 / 9x^3 -99x^2 or A = 8/9x^2(x-11)
2007-10-07 17:59:19 · answer #2 · answered by combat_wombat121 2 · 0⤊ 0⤋
multiply these two expressions:
8x/(x^2-121) x (x+11)/9x^3
simplify,
= 8x+88/ 9x^4 -1089x^2
I think
2007-10-07 17:29:40 · answer #3 · answered by Anonymous · 0⤊ 0⤋
8x/[(x+11)(x-11)][(x+11)/8x^3
= 1/(x^2(x-11))
2007-10-07 17:20:29 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
the formula for the area of a rectangle is A=LW [area is equal to length multiplied by its width.
**All you have to do is plug them in.
2007-10-07 17:17:53 · answer #5 · answered by notcha_business09 3 · 0⤊ 0⤋
please rephrase your question its confusing
2007-10-07 17:18:33 · answer #6 · answered by @YD@y 4 · 0⤊ 0⤋