please read the qusetion in the discription?

Question

A car moving westward along a straight, level road increases its velocity uniformly from 24 m/s to 25 m/s in 10 s.
(a) What is the car's acceleration?
m/s2 (westward)
(b) What is its average velocity?
m/s (westward)
(c) How far did it move while accelerating?
m


I tried to solve this out but, for some strange reason im not able to come up with the correct answer. Can anyone show me how to solve this problem. Please.

Answer 1

Okay, a physics question, you know that acceleration=Change in velocity/time, so you take 25m/s-24m/s and divided by 10 secs. That gives you .1m/s^2 for part A. Then for average velocity you take the two velocities and divided them by 2 so 25+24/2, which is 24.5. The for the distance part, d=v0t+1/2at^2, where D is distance, v0 is the initial velocity, a is acceleration and t is time. So plug everything in like this, (24)(10)+1/2(.1)(10^2) and you get 245m. Hope that helped

Answer 2

Velocity increases by 1 m/s in 10 secs.
So that's 0.1m/s^2
Average velocity is (24+25)/2 or 24.5 m/s.
Since it travelled for 10 secs at 24.5 m/s on average,
it must have travelled 245 m (I assumes that is metres).