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the qusetions are as follows:
A car moving westward along a straight, level road increases its velocity uniformly from 24 m/s to 25 m/s in 10 s.
(a) What is the car's acceleration?
m/s2 (westward)
(b) What is its average velocity?
m/s (westward)
(c) How far did it move while accelerating?
m


I thought to figure this problem out I would have to take the final velocity (25m/s) minus the original velocity (24 m/s) diveded by the time (10 s). which would give me .1 m/s/s (.1 m/s^2) . But, this stupid webassign homework is kicking my ***.

2007-10-07 08:32:36 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

(a) v=u+at so a=(v-u)/t
>>>>>>>>>>>=(1)/10
>>>>>>>>>>>=0.1m/s/s
(b) average velocity = (initial velocity + final velocity)/2
>>>>>>>>>>>>>> = (49)/2
>>>>>>>>>>>>>> = 24.5m/s
(c) v^2 = u^2 +2ax
>>>x=(v^2 - u^2)/2a
>>>>=(625-576) / 2(0.1)
>>>>=(49) / 0.2
>>>>=245m

2007-10-07 08:56:55 · answer #1 · answered by Helen B 5 · 0 0

Helen B gave you good answers. If your webassign says no --
you said "m/s2 (westward)" for acceleration in your question instead of m/s^2. Could it be that you made that mistake when you put your answer into webassign?

A simpler way to answer c)

Average velocity * time

2007-10-07 16:52:44 · answer #2 · answered by sojsail 7 · 0 0

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