Rex rode his bicycle 300 kilometers. Three tires were used equally in accumulating this distance. How many kilometers of wear did each tire sustain?
2007-10-07 08:02:33 · 11 answers · asked by Brian M 1 in Science & Mathematics ➔ Mathematics
ahah wow i thought it had to do with physics with the wear and whatnot..w.e. thanks guys.. its 200km btw
2007-10-07 08:16:21 · update #1
Cookie Monsta Busta..how old are u?
2007-10-07 08:16:59 · update #2
I would say each tire got 200km of wear, because you use two tires at a time. So, each tire is being used 2/3 of the time:
(2/3)*(300) = 200.
200 kilometers of wear per tire.
Good luck.
2007-10-07 08:09:11 · answer #1 · answered by tsully87 3 · 5⤊ 0⤋
200 km each tire. Since two tires at a time must be used, they all go 2/3 the distance.
2007-10-07 08:11:17 · answer #2 · answered by marystoy_2000 5 · 1⤊ 0⤋
I feel like this is a trick question because you have to have 2 tires on the bike all the time there for 1 of the tires would get more use than the other 2 no matter what way you switched them around.
2007-10-07 08:16:53 · answer #3 · answered by Bethnee 2 · 0⤊ 2⤋
Each tire bore 200 km of wear
2007-10-07 08:11:43 · answer #4 · answered by ironduke8159 7 · 1⤊ 0⤋
200
2007-10-07 08:10:44 · answer #5 · answered by KaribuTanzania 3 · 1⤊ 0⤋
If I understood it correctly, 300/3= 100. That's all? How much is the discount?
Edit: 200? (Sighs.) That's...
but I think I agree with the 2/3 answer down there.
2007-10-07 08:08:37 · answer #6 · answered by Palestini Detective 4 · 0⤊ 4⤋
100 kilometers. Because each tire took you 100 kilometers.
2007-10-07 08:07:02 · answer #7 · answered by Anonymous · 0⤊ 3⤋
200km, not 300 - a bicycle has two wheels.
2007-10-07 08:10:19 · answer #8 · answered by Helen B 5 · 2⤊ 0⤋
300 kilometers, 3 tires. Come on, you can't divide 300 by 3?
2007-10-07 08:05:49 · answer #9 · answered by Anonymous · 0⤊ 5⤋
300/3=100 km cuz you have to make them even out with amount of wear. this isn't that hard. how old are you?
2007-10-07 08:09:47 · answer #10 · answered by bill 2 · 0⤊ 3⤋