Assume you are a medieval knight attacking a castle with a cannon. The ball leaves the cannon with a speed of 49.3 m/s. The barrel's angle with respect to the ground is 44.5 degrees, and you make a perfect hit on the tyrant's chamber which is at the same level as the cannon's muzzle (H=0 m). What is the time of flight of the cannon ball?
2007-10-07 07:36:01 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Forget the horizontal portion of problem; think only about the vertical.
If the velocity is 49.3 m/s at an angle of 44.5 degrees, what is the vertical component? Call it V
You know the acceleration due to gravity. How long would it take for gravity to slow a ball thrown straight up with velocity V, ignoring air resistance? Call this Tu
Now how long would it take for the ball to come back to where it started (where it started because the tyrant's chamber is the same height as the cannon muzzle)? Call that Td.
Total time is time up plus time down.
You can also figure out how far away the tyrant's chamber is (assuming no air resistance :-)
You now know the total time. You can also compute the horizontal component of the muzzle velocity.
Distance = velocity x time
2007-10-07 16:13:26 · answer #1 · answered by simplicitus 7 · 0⤊ 0⤋
Just tell them medieval knights didn't use cannons, they had other soldiers fire them. So in that case, there is no answer.
2007-10-09 07:28:05 · answer #2 · answered by mercierarmory 5 · 0⤊ 0⤋