(3x^2-7x+5)+(-2x^2+7x-8)?

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Algebra help! the question states perform the indicated operation

2007-10-07 07:17:56 · 5 answers · asked by nabs l 1 in Science & Mathematics ➔ Mathematics

x^2-3
the 7xs cancel out and u left with 1x^2 and -8-5 = 3

2007-10-07 07:20:50 · answer #1 · answered by programhelp 2 · 0⤊ 0⤋

(3x^2-7x+5)+(-2x^2+7x-8)
=3x^2-7x+5-2x^2+7x-8
=x^2-3. ANS.

2007-10-07 14:22:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋

3x^2-7x+5-2x^2+7x-8
x^2-3

2007-10-07 14:26:25 · answer #3 · answered by notemoenough 2 · 0⤊ 0⤋

Do it, term by term
3x2-2x2
-7x+7x
5-8
collect the remainders.

2007-10-07 14:22:25 · answer #4 · answered by cattbarf 7 · 0⤊ 0⤋

x^2 - 3

(x + sq root 3) ( x - sq root 3)

2007-10-07 14:20:53 · answer #5 · answered by Steve B 6 · 0⤊ 0⤋