2007-10-07 06:04:44 · 3 answers · asked by crystal_clear_girl238 1 in Science & Mathematics ➔ Mathematics
since the line is parallel to the given line, it should be
2y-6x=k (where k is unknown)
but it passes through (-2,1). so,
2(-2)-6(1)=k
k=-10
therefore the required line is 2y-6x=-10 or 3x-y=5
2007-10-07 06:08:54 · answer #1 · answered by may_5 2 · 0⤊ 0⤋
The general equation for a linear equation (straight lines) is y = mx+c, where
y = y-value
x = x-value
m = gradient/slope
c = y-intercept
2y - 6x = 9 can therefore be re-written as
y = 3x + 4.5
For the other line, since it is parallel to our original equation, the slope has to be the same, i.e. m = 3
Substitute the new x- and y- values...
y = mx + c
1 = 3(-2) + c
c = 7
Therefore, the equation of the new line is y = 3x + 7
2007-10-07 13:19:40 · answer #2 · answered by w_gy_cc 2 · 0⤊ 0⤋
Slope of given line is 6/2 = 3
so the required || line also has a slope of 3
y = 3x+b
Since line goes through (-2,1) we have:
1 = 3(-2) +b --> b = 7
So equation is y = 3x + 7
2007-10-07 13:10:48 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋