parallel to the line y=4x+1, and that passes through point (2,3)?

Answer 1

y = 4X - 5

since they're parallel, the rate of change (4) stays the same. Then just plug in the numbers and solve.

Answer 2

In order to solve this question, you must know what form the line that you have specified is written in.

The line that you have specified is in the form:

y = mx + b

where m is the slope and b is the y-intercept. Therefore, looking back at your equation:

y = 4x + 1

the slope, m, equals 4. Because parallel lines are equal in their slopes, the slope of the parallel line must also equal 4. Thus, an equation can be written:

y = 4x + b

Now, to solve for b, which is the y-intercept, plug in the point that is in your question, (2, 3), for x and y, respectively:

y = 4x + b
= 3 = 4(2) + b

Now multiply 4 and 2:

3 = 4(2) + b
= 3 = 8 + b

Next, subtract 8 from both sides of the equation to solve for b:

3 = 8 + b
= 3 - 8 = 8 + b - 8
= -5 = b

Finally, plug this back into the original equation, y = 4x + b, in order to obtain the equation of the line and your answer:

y = 4x + b
= y = 4x + -5

This is your answer: y = 4x + -5 or y = 4x - 5.

Hope this helps!

Answer 3

a line parallel to y = 4x + 1 is a line which has the same slope, but a different y-intercept.

For a line y = mx + b
m is the slope, and b is the y-intercept.

So a line parallel to y = 4x + 1 is of the form y = 4x + b.

We want the parallel line y = 4x + b to pass through point (2, 3), so we plug in the values for (x, y) and solve for b.
y = 4x + b
3 = 4*2 + b
3 = 8 + b
3 - 8 = 8 + b - 8
-5 = b

so the line is y = 4x - 5

Answer 4

the slope of the given line = 4

slope of rquired line = 4 (since lines are parallel)

equation of required line in point slope form

y - y1 = m(x-x1)

here m = 4

x1= 2

y1 = 3

y -3 = 4(x-2)

y - 3 = 4x - 8

The equation of the required line is

y = 4x - 5

Answer 5

m = 4
y - 3 = 4 (x - 2)
y = 4x - 8 + 3
y = 4x - 5