A ball thrown horizontally at 25 m/s travels a horizontal distance of 50 m before hitting the ground.?

Question

A ball thrown horizontally at 25 m/s travels a horizontal distance of 50 m before hitting the ground. From what height was the ball thrown?
m

Answer 1

50/25 = 2s

.5(9.8)(2^2) = 19.6m

Answer 2

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Split it up into x and y components. The time it takes for the ball to travel 50 meters horizontally will be equal to how long it takes for it to fall vertically. There is no acceleration in the x direction: Vx = d/t 25 m/s = 50 m/t t = 2 s Initial velocity in the y direction (Vy) = 0 m/s because the ball is thrown horizontally and not at an angle: d = (Vy)t + 1/2at^2 d = 0 + (1/2)(9.8 m/s^2)(2 s)^2 d = 19.6 m high

Answer 3

Horizontal Distance

Answer 4

Projectile problems involve separating horizontal components
and vertical components of motion which occurs in the
same time interval.

In this case the vertical component is
initially zero, except for the unknown h. Now the horizontal
velocity component is constant for the flight of the ball.
Time of flight is then 50 m /25 m/s= 2 sec.
In this same 2 sec. the ball descended through a vertical
distance .5*10*2^2 = 20 m. = h.

Answer 5

In the horizontal direction:
distance = velocity*time
d=v*t
50=25*t
t=2

So, the ball was in the air for two seconds.


In the vertical direction:
0=1/2at^2 + vi +xi
0=1/2(-9.8)(2^2) +0 +xi
0= -19.6 + xi
19.6 = xi

The ball was thrown from a height of 19.6 meters.

Good luck!

Answer 6

It travels for 50m at a velocity of 25m/s horizontally, that means it travelled for 2 seconds..
So, it must have been thrown from a height of 1/2(9.8)(2)(2) = 19.6 m
where 9.8m/s2 is the acceleration due to gravity.

Answer 7

The ball goes for 2 sec during which it falls D=1/2(g)t**2 = 64 ft

Answer 8

19.6 meters.
Now -you- need to figure out how I got the answer. And you need to do it -before- your next exam.

Doug