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Calculate the work done (in Joules) when 45.6 g of tin dissolves in excess acid at 1.03 atm and 23deg.C. Assume ideal gas behavoir

Sn(s) + 2H(+)(aq) ---> Sn(2+)(aq) + H2

2007-10-07 05:20:02 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Sn(s) + 2H(+)(aq) ---> Sn(2+)(aq) + H2
45.6 g of tin <==> 0.384 Mol of tin
<==> produce 0.384 Mol of H2
PV = nRT = 0.384*8.314*296 (J) = 945J
945J is the work done.

2007-10-08 17:27:49 · answer #1 · answered by Hahaha 7 · 0 0

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