If p and q are two prime numbers and p>q>3 . Prove that the sum p+q is divisible by 12.
The previous has a typo. Sorry because I do not know how to reedit the question so I ve got to post it again.
2007-10-07 05:05:00 · 3 answers · asked by thlee 2 in Science & Mathematics ➔ Mathematics
5, 7
7, 29
11, 37
Although, this wont be true with all random primes (because then we would've already solved the Rhiemann Hypothesis), it can be true with specific numbers. Like 5 and 7.
5 + 7 = 12
12/12 = 1
Unfortunately the people below can't seem to realize, this doesn't say, "prove true for all primes", it says prove this equation true. It just says that the numbers used are prime.
The correct answers for this are infinite as are numbers.
2007-10-07 05:09:27 · answer #1 · answered by jpferrierjr 4 · 0⤊ 2⤋
Before attempting to answer, I tried to check if it is correct. Taking p = 11 and q = 7.
Both p and q are prime and the condition p > q > 3 is also satisfied.
But p + q = 18 is not divisible by 12.
Again, taking p = 17 and q = 11,
p + q = 28 is not divisible by 12.
So, how can I prove what is untrue ?
2007-10-07 05:12:07 · answer #2 · answered by Madhukar 7 · 0⤊ 1⤋
This statement is false: Take p = 47 and q = 5.
The sum is 52, which is divisible by 4 and not by 3.
2007-10-07 05:11:18 · answer #3 · answered by steiner1745 7 · 1⤊ 1⤋