what remainder does 3 to the power of 51 divided by 9 leave? plz explain properly?

Answer 1

3^51 / 9 = 3^51 / 3^2 = 3^(51 - 2) = 3^(49)

now this number when expanded is always an integer

==> Remainder is zero (0)

Answer 2

3 to the power of 51 divided by 9 = 3 to the power of 51 divided by 3 to the power of 2 = 3 to the power of 51 - 2 = 3 to the power of 49 3 p1= 3 3 2=9 3 3 = 27 3 4 = 81 3 5 = ...3 3 6 = ...9 3 7 = ...1 3 8 = ...3 So it repeats at every 4 so the remainder of 3 49 is 3

Answer 3

3 to the power of 51 divided by 3 to the power of 2 (because 9 is 3x3) = 3 to the power 49 (because 51-2= 49)

there is no remainder.

Answer 4

Well, 9 = 3^2 (where ^ means "to the power of")
and so 3^51 divided by 9 is 3^(51-2) = 3^49
And so 9 divides 3^51 evenly, and the remainder is 0

Answer 5

3^51 divided by 3^2 is 3^49 again it will be divided by 3^2 and so on till u get a remainder that will be 3^1 which is 3 itself

Answer 6

3^51 / 9 = 3^51 / 3^2,
When you divide, you subtract exponents.
3^ (51 - 2) = 3^49.
Remainder = 0 [answer].

Answer 7

We first change 9 into base 3 like 3 to the power of 2.

Now when you divide numbers with the same bases but different exponents, you apply the laws of exponents where you subtract the exponent of the dividend with the exponent of the divisor.

So when you divide 3 to the power of 51 by 3 to the power of 2 is equal 3 to the power of 49.

Hope I helped.

Answer 8

the ans is 3^49 because i will written as 3^51/9so 3^51/3^2
3^51-2 so 3^49it was in the formula a^m/a^n=a^m-n

Answer 9

(3^51)/9
=(3^51)/(3^2)
=3^49 and remainder is 0.

Answer 10

first 3 X ? =51 then divide it by 9