how many moles of ions are in 1 mole of iron(iii) sulphate 7 water?

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2007-10-07 01:27:26 · 4 answers · asked by kenny 1 in Science & Mathematics ➔ Chemistry

Fe2 (SO4)3

2 moles of Fe 3+ ions

3 moles of (SO4)2- ions

Therefore total number of ions in 1 mole of Iron (III) Sulphate 7 water is:

5 moles

2007-10-07 01:51:08 · answer #1 · answered by Kean 3 · 1⤊ 0⤋

the formula for iron(iii) sulphate is Fe2(SO4)3

there are 2 moles of iron and 3 moles of sulphate giving 2 + 3 = 5 moles of ions in water.

2007-10-07 01:49:38 · answer #2 · answered by Anonymous · 0⤊ 0⤋

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2016-05-17 02:25:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋

Fe2(SO4)3 - therefore five moles of ions.

2007-10-07 01:30:45 · answer #4 · answered by Gervald F 7 · 0⤊ 0⤋