A packet of mixed dry fruits weighs 700 gm. If it is made up of x gm and y gm Dry fruits (Rates 288 per kg and 112 per kg) find x and y. Cost of the packet is 216
2007-10-06 21:50:39 · 5 answers · asked by Angry dude 2 in Science & Mathematics ➔ Mathematics
There is no answer to this problem.
If the packet were made up of 700g of the first fruit, that would be 700g * 288/kg / 1000 = 201.6
So even if the packet was completely composed of the most expensive fruit, it can't cost 216.
If you try to solve it you'll get an answer like:
x = 781.81
y = -81.81
But this obviously makes no sense.
Please check your problem again.
2007-10-06 22:05:53 · answer #1 · answered by Puzzling 7 · 2⤊ 0⤋
the cost of 1 kg with same composition as the packet is 216/0.7
so this would correspond to a price by kg of 216/0.7 =308/kg
So there is no solution since the prices by kg are all lower that this value
2007-10-06 22:02:17 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
x + y = 0.7 kg
288x + 112y = 216
using my powerful calculator (the one with solver)
x = 781.82 grams
y = -81.82 grams
that's what the given leads to, maybe your question had a typo error.
* btw, you should write grams as g, not gm.
2007-10-06 22:13:09 · answer #3 · answered by dudellbytez 1 · 0⤊ 0⤋
288x/1000 + 112y/1000 = 216
Sub in y = (700 - x) into the equation and solve for x
2007-10-06 22:06:44 · answer #4 · answered by Bananaman 5 · 0⤊ 0⤋
By calculation:
x = 781.82grams
y = -81.82 grams
The answer is crystal clear. The question is wrong.
2007-10-07 07:44:17 · answer #5 · answered by Ajay-webmaster 2 · 0⤊ 0⤋