a gun is fired with angle of elevation 30 degrees.what is the muzzle speed if the max height of shell is 500 m

Question

tnx for da help^ ^

Answer 1

use this equation in a vertical direction (or y direction):
(Vfinal)^2 - V(initial)^2 = 2ax
Vfinal = 0 ... when the shell reaches the height before dropping down by gravity, the vertical velocity is 0.
a = -g (or -10).
And if your draw out the diagram, you'll find Vinitial = Vsin(angle)

After simplifying and everything: (Vsin(30))^2=2(10)(500) = 10000
Vsin(30) = 100
V = 100/sin(30) = 200 m/s

Answer 2

enable v_y characterize the vertical area of the preliminary velocity, and enable h_max characterize the optimal suitable of the trajectory. assume there is not any air resistance and this occurs in earth-floor gravity. you have been gaining understand-how of a few equations for action decrease than consistent acceleration, which incorporates h = one million/2 a t^2 + v0 t + h0. by way of changing for t on an identical time as v = 0, you are able to desire to remodel that into precise right here equation: h_max = (v_y)^2 / (2g) Fill in 600m for h_max and 9.8 for g, and therapy for v_y. Now you have the vertical area of the preliminary velocity. Now use the 30° attitude and a few common trigonometry to locate the full value of that preliminary velocity.

Answer 3

let V be the intial speed

there are two speed components. Horizonal speed and vertical speed. Since we are given the hieght, which is a vertical measurement, we only need vertical speed

Verical speed = Vsin(30)

Vf^2 = 2ad + Vi^2

at the maximun height, the speed is 0m/s.
acceleration due to the earth is -9.8 m/s^2

0^2 = 2(-9.8)(500) + (Vsin(30))^2
9800 = .25V^2
V^2 = 39,200
V = 198 m/s (rounded) <== answer

Answer 4

They are all semi correct but a little off. I had the same question and the program specifies to use 9.8 for gravity, In the equation just replace 10 with 9.8 and it works. Not like you care anymore. XD

Answer 5

Need more info.
A .204 ruger muzzle velocity is 4225fps.
a.223 is about 3000fps ect...

Answer 6

how long does it take to get there. you need the time to get the velocity